Biology 20
Hardy-Weinberg problems: Answers
in bold
1.
We have always thought that Rudolph the red-nosed
reindeer was a one of a kind. However in
the remote reaches of
q2 = 3/100 = .03 à q =
à
q = .17 frequency of the recessive
allele
p + q =1 à
p = 1 – q à p = 1 - .17 = .83 frequency of the dominant allele
p2 + 2pq + q2 =1 2pq
à
2(.83)(.17) = .28
or 28% of population that’s heterozygous
Aa x Aa à (2pq) (2pq) à (.28)(.28) = .078 or 7.8%
2.
During the holiday season the dominantly inherited gene
for overspending often times kicks into high gear. Roughly 80% of shoppers in The Shops at
20% of the population is recessive for the overspending gene
NOTE:
you’ll need to always start by determining the recessive allele, NOT the
dominant one
q2 = 20% or .20 à q =
à
q = .45 frequency of the recessive
allele
p + q =1 à
p = 1 – q à p = 1 - .45 = .55 frequency of the dominant allele
p2
+ 2pq + q2 =1 AA
= p2 à
.552 = .30 or 30% are
homozygous dominant
p2 + 2pq + q2 =1 Aa = 2pq à 2(.55)(.45) = .495 or 49.5% are heterozygous
3. Elf is one of the taller elves, but he’s not alone. The allele for increased height is recessively inherited and actually occurs in about 5% of the elf population working in Santa’s workshop.
q2 = 5% or .05 à q =
à
q = .22 or 22% frequency of the
recessive allele